SOLUTION: A solution if 52% fertilizer is to be mixed with a solution of 22% fertilizer to form 90 liters of a 42% solution. How many of the 52% solution must be used?

Question 710351: A solution if 52% fertilizer is to be mixed with a solution of 22% fertilizer to form 90 liters of a 42% solution. How many of the 52% solution must be used?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
This one is the same general problem as question #710342. Different materails, different mixture unit, different values; but the same problem.

VARIABLES
High concentration fertilizer percent, H =52%
Low concentration fertilizer percent, L =22%
Target percent wanted, T = 42%
Amount of High conce. to use, v
Amount of Low conce. to use, u
Amount of target mixture produced, M = 90 Liters

This system can be formed from the description and question

If we use the second equation as , we can substitute it into the rational equation and solve that one for u, giving us this:

Now, just substitute the values and compute u.
We can then go to our simpler-looking expression for v and find (compute) it, too.
RELATED QUESTIONS
A solution of 64% fertilizer is to be mixed with a solution of 22% fertilizer to form 84... (answered by josgarithmetic)

A solution of 68% fertilizer is to be mixed with a solution of 32% fertilizer to form 108 (answered by checkley77)

A solution of 54% fertilizer is to be mixed with a solution of 27% fertilizer to form 135 (answered by mananth)

A solution of 49% fertilizer is to be mixed with a solution of 28% fertilizer to form 252 (answered by josgarithmetic)

A solution of 69% fertilizer is mixed with a solution of 20% fertilizer to form 490... (answered by josgarithmetic)

a solution of 72% fertilizer is to be mixed with a 26% fertilizer to form 230 liters of a (answered by stanbon)

A solution of 64% fertilizer is to be mixed with a solution of 22% fertilizer to form 84... (answered by josmiceli)

a 20% solution of fertilizer is to be mixed with a 80% solution of fertilizer in order to (answered by checkley77)

A 20% solution of fertilizer is to be mixed with a 80% solution of fertilizer in order to (answered by KMST)