SOLUTION: Two consecutive positive even integers whos product is 80

SOLUTION: Two consecutive positive even integers whos product is 80

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Question 700644: Two consecutive positive even integers whos product is 80
Answer by unlockmath(1688) (Show Source): You can put this solution on YOUR website!
Hello,
Let's use x and x+2 to represent the numbers.
x(x+2)=80
x^2+2x-80=0
Factor:
(x+10)(x-8)=0
Solve for x:
x=-10
x=8
Since we want positive integers 8 & 10 are the winners.
Make sense?
RJ
www.math-unlock.com
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