SOLUTION: can you define the variable, write an inequality, and solve the problem. It says: The sum of two consecutive positive even integers is at most 15. What are the possible pairs of i

Question 698675: can you define the variable, write an inequality, and solve the problem. It says: The sum of two consecutive positive even integers is at most 15. What are the possible pairs of integers.
Answer by sofiyac(983) (Show Source): You can put this solution on YOUR website!
It says: The sum of two consecutive positive even integers is at most 15. What are the possible pairs of integers.
consecutive positive even integers...so first one would be 2x, we mulitply x by two in order to make sure it's even (divisible by 2). Then the next even integer would be 2x+2. Now add them and make has to be less than or equal to 15.

subtract 3 from each side
divide each side by 4
so if x is less than or equal to 3 than x could be 1 or 2 or 3. In which case our first combination would be 2x and 2x+2 so 2*1 and 2*1+2. Then plug in x=2 and x=3. So the possible pairs of integers are
1) 2 and 4
2) 4 and 6
3) 6 and 8
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