SOLUTION: Factor 7x^2-14x-56 and factor 9x^2-336x+27

Question 681613: Factor 7x^2-14x-56
and
factor 9x^2-336x+27
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
Factor 7x^2-14x-56
First factor out the greatest common factor. In this case all three terms are divisible by 7.

Now we know that we have:
7(x+___)(x-___) Because the last term is negative.
We need to find to numbers that multiply to give -8 (the last term) but add to get -2 (the middle term)
-4*2 = -8 and -4+2=-2

I think the next one might be a type-0, so I will do it as you wrote it, then do it based on my experience of what the type-o might be.

factor 9x^2-336x+27
The all numbers are divisible by 3.

That's all you can do.

I think you meant:
factor
Everything is divisible by 9

-3*-1=3 and -3+-1=-4

Hope that helped. Happy Calculating.
RELATED QUESTIONS
Factor 14x^3-7x^2+6x-3 (answered by jim_thompson5910)

Factor... (answered by oberobic,richwmiller,mananth)

factor:... (answered by Jessmh123)

factor 9x^2-18xy-7x+14y (answered by jim_thompson5910)

Factor by grouping 7x^3-14x^2-1x +... (answered by nerdybill)

how to factor 7x^3... (answered by ptth176)

Factor... (answered by babynarah2007)

5x^2-14x-3... (answered by CharlesG2)

factor... (answered by stanbon)