SOLUTION: Solve {{{4^x=2}}}
There are a couple of ways to solve this. You can use logs, however, in this case it is easiest to equate the bases.
{{{4^x=2}}}
{{{(2^2)^x=2}}}
{{{2^(2x
Algebra.Com
Question 681001: Solve
There are a couple of ways to solve this. You can use logs, however, in this case it is easiest to equate the bases.
once the bases are the same, then the exponents are equal and you can solve for x.
Hope that helped. Happy Calculating!
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
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