SOLUTION: How can you write expression with rationalized denominator? Squareroot3-squareroot6. / squareroot3+square root6

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Question 678278: How can you write expression with rationalized denominator?
Squareroot3-squareroot6. / squareroot3+square root6

Found 2 solutions by stanbon, pmatei:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
write expression with rationalized denominator?
Squareroot3-squareroot6. / squareroot3+square root6
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= (sqrt(3)-sqrt(6)) / (sqrt(3)+sqrt(6))
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Multiply numerator and denominator by sqrt(3)-sqrt(6)
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= [(sqrt(3)-sqrt(6))(sqrt(3)-sqrt(6))] /[3-6]
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= [3 - 2sqrt(18) +6] / (-3)
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= [9-6sqrt(2)] / (-3)
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= [-3 + 2sqrt(2)]
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Cheers,
Stan H.
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Answer by pmatei(79)   (Show Source): You can put this solution on YOUR website!
You take advantage of , by considering your denominator as either or and multiplying both numerator and denominator with the other paranthesis in the formula:
In your case the denominator is the , thus you multiply with :





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