SOLUTION: Determine the domain and range: y = f(x) = 6x^2 +3.

Question 677758: Determine the domain and range:
y = f(x) = 6x^2 +3.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
The vertex of y = 6x^2 +3 is (0,3). The min is y = 3 because this is the y coordinate of the vertex and the leading coefficient is positive.

Domain: The set of all real numbers (this is true for any polynomial)

Range: The set of all real numbers such that (this is because the min is y = 3). Basically any number greater than or equal to 3 is part of the range.

In interval notation,

Domain: $\left(-\infty,\infty\right)$

Range: $[3,\infty)$
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