SOLUTION: 4(b+3) = (b-3)/7
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Question 677529
:
4(b+3) = (b-3)/7
Answer by
jim_thompson5910(35256)
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4(b+3) = (b-3)/7
7*4(b+3) = b-3
28(b+3) = b-3
28b+84=b-3
28b=b-3-84
28b-b=-3-84
27b=-3-84
27b=-87
b=(-87)/(27)
b=-29/9
So the solution is b=-29/9