SOLUTION: What volume in ml of a 60% hydrochloric acid solution must be added to 100ml of 30% hydrochloric acid solution to make 36% hydrochloric acid solution? (PS: could you explain this

Question 668237: What volume in ml of a 60% hydrochloric acid solution must be added to 100ml of 30% hydrochloric acid solution to make 36% hydrochloric acid solution? (PS: could you explain this one for the steps?). Thanks
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
What volume in ml of a 60% hydrochloric acid solution must be added to 100ml of
30% hydrochloric acid solution to make 36% hydrochloric acid solution?
:
let x = the vol of 60% acid solution required
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Since this will be combined with 100 mg of 30% solution, the result will be (x+100) mg
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Use the decimal equiv
.60x + .30(100) = .36(x+100)
,60x + 30 = .36x + 36
.60x - .36x = 36 - 30
.24x = 6
x = 6/.24
x = 25 mg of 60% acid required
:
:
Confirm this in the original mixture equation
.60(25) + .30(100) = .36(125)
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Was this "step by step" enough for you, any questions here? C
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