SOLUTION: The perimiter of a rectangle is 38 units. Two sides are X, the other two are 2X - 5. How do I find X?
Algebra.Com
Question 658860: The perimiter of a rectangle is 38 units. Two sides are X, the other two are 2X - 5. How do I find X?
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
The perimiter of a rectangle is 38 units. Two sides are X, the other two are 2X - 5. How do I find X?
.
perimeter = total length of all four sides
38 = x + x + 2x-5 + 2x-5
38 = x + x + 2x + 2x-10
38 = 6x-10
48 = 6x
8 = x
.
answer: 8 units
RELATED QUESTIONS
find the perimeter of a rectangle if the sides are x/2x-5 and the other is... (answered by checkley71)
Two opposite sides of a square with length x are increased by 3 units each and the other... (answered by Theo)
Two sides of a rectangle are parallel to each other and are doneted as y. The other two... (answered by jim_thompson5910,josgarithmetic)
if two regular polygonjs each have 47 equal sides and the perimiter of one is 47 times... (answered by Alan3354)
The consecutive sides of a rectangle are (x+11) units and (3x+8) units, and the perimeter (answered by mananth)
i have a rectangle w/a perimiter of 98 ft.
i need to find the value of x.
the height... (answered by bonster)
The perimeter of a triangle is 2x + 5. Find the 3rd side if the other two sides are X^2-6 (answered by Earlsdon)
- Two angles with measures os (2x – 7) and (3x – 3) are complementary. Find x
x = 45
x... (answered by Alan3354)
Two sides of a triangle are equal length. The length of the third side exceeds the length (answered by Alan3354)