You can
put this solution on YOUR website!A)f(x)= 2/3x^(3/4) + 3/4x^(2/3)+ 5/6x^(2/3)
B) f(x)= 2/5x^(3/2) + 5/6x^(3/4) + 5/6x^(3/2)
C) f(x)= 3/4x^(2/3) +5/6x^(3/2) + 3/4x^(3/2)
A) f'(x) = (2/3 * 3/4)x^(-1/4) + (3/4 * 2/3)x^(-1/3) + (5/6 * 2/3)x^(-1/3)
= x^(-1/4)/2 + x^(-1/3)/2 + 5x^(1/3)/9
= 1/(2x^(1/4)) + 1/(2x^(1/3)) + 5/(9x^(1/3))
B) f'(x) = (2/5 * 3/2)x^(1/2) + (5/6 * 3/4)x^(-1/4) + (5/6 * 3/2)x^(1/2)
= 3x^(1/2)/5 + 5x^(-1/4)/8 + 5x^(1/2)
= 3x^(1/2)/5 + 5/(8x^(1/4)) + 5x^(1/2)
C) f'(x) = (3/4 * 2/3)x^(-1/3) + (5/6 * 3/2)x^(1/2) + (3/4 * 3/2)x^(1/2)
= x^(-1/3)/2 + 5x^(1/2)/4 + 9x^(1/2)/8
= 1/(2x^(1/3)) + 5x^(1/2)/4 + 9x^(1/2)/8
You can
put this solution on YOUR website!I am assuming that the fractions after the variables are exponents, let me know if I'm not interpretting you correctly:
calculate the first derivatives f(x) for each of the following:
show all work
A)f(x)= 2/3x3/4 + 3/4x2/3+ 5/6x2/3

f'(x)=

f'(x)=

f'(x)=

:
B) f(x)= 2/5x3/2 + 5/6x3/4 + 5/6x3/2

f'(x)=

f'(x)=

f'(x)=

:
C) f(x)= 3/4x2/3 +5/6x3/2 + 3/4x3/2

f'(x)=

f'(x)=

f'(x)=

Happy Calculating!!!