SOLUTION: Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis. y = 3x2

Question 618461: Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.
y = 3x2 12x + 12

Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.
y = 3x2+12x + 12
complete the square
y=3(x^2+4x+4)+12-12
y=3(x+2)^2
This is an equation of a parabola that opens upwards.
vertex: (-2,0)
vertex lies on the x-axis
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