SOLUTION: The length of a rectangle is 2ft longer than its width. Find the dimensions of the rectangle such that the perimeter of the rectangle is 845ft
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Question 612919: The length of a rectangle is 2ft longer than its width. Find the dimensions of the rectangle such that the perimeter of the rectangle is 845ft
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
P = 2L + 2W
845 = 2(W+2) + 2W
845 = 2W+4 + 2W
845 = 4W+4
845-4 = 4W
841 = 4W
841/4 = W
W = 841/4
Now that you know W, use it to find L
Remember that L = W+2
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