SOLUTION: Find the center of the circle: x^2+y^2+2x+18y-8=0
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Question 609749
:
Find the center of the circle:
x^2+y^2+2x+18y-8=0
Answer by
richwmiller(17219)
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(-1,-9)
(x+1)^2+(y+9)^2-90 = 0