SOLUTION: Find the center of the circle:
x^2+y^2+2x+18y-8=0
Algebra.Com
Question 609749: Find the center of the circle:
x^2+y^2+2x+18y-8=0
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
(-1,-9)
(x+1)^2+(y+9)^2-90 = 0
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