SOLUTION: I need help solving this math problem : Find two integers whose product is 77 such that one of the integers is three less than twice the other integer.

Question 604724: I need help solving this math problem :
Find two integers whose product is 77 such that one of the integers is three less than twice the other integer.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find two integers whose product is 77 such that one of the integers is three less than twice the other integer.
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Equations:
xy = 77
x = 2y-3
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Substitute for "x" and solve for "y":
(2y-3)y = 77
2y^2-3y = 77
2y^2-3y-77 = 0
2y^2 -14y+11y-77 = 0
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2y(y-7)+11(y-7) = 0
(y-7)(2y+11) = 0
y = 7 or y = -11/2
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Integer solution:
y = 7
Therefore x = 11
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Cheers,
Stan H.
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