SOLUTION: 3x(x-3)=2x(x+2)+6, so far I've got 3x^2-9x-2x^2-4x-6=0, then x^2-13x-6=0 but after this I'm lost?

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Question 602851: 3x(x-3)=2x(x+2)+6, so far I've got 3x^2-9x-2x^2-4x-6=0, then x^2-13x-6=0 but after this I'm lost?
Found 2 solutions by Alan3354, flame8855:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
3x(x-3)=2x(x+2)+6, so far I've got 3x^2-9x-2x^2-4x-6=0, then x^2-13x-6=0 but after this I'm lost?
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=193 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 13.4462219947249, -0.446221994724902. Here's your graph:

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You can do it by completing the square, also.

Answer by flame8855(424)   (Show Source): You can put this solution on YOUR website!
x^2-13x-6=0 a = 1 , b= -13 , c = -6
delta = b^2-4ac = 169+24=193
x1= -b+delta^2/2a = (13+193^1/2) /2
x2= -b-delta^2/2a = (13-193^1/2) /2
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