# SOLUTION: How do I find the maximum area for a rectangle with a fixed perimeter of 120

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 Question 602737: How do I find the maximum area for a rectangle with a fixed perimeter of 120Found 2 solutions by rfer, stanbon:Answer by rfer(12666)   (Show Source): You can put this solution on YOUR website!a square is max' 120/4=30 30*30=900 sq units Answer by stanbon(57384)   (Show Source): You can put this solution on YOUR website!): How do I find the maximum area for a rectangle with a fixed perimeter of 120 ---- Area = L*W Perimeter = 2L + 2W ------ 2L+2W = 120 L + W = 60 W = 60-L ----- Substitute into the Area formula: A = L(60-L) A = 60L - L^2 ----- Rearrange: A = -L^2+60L Maximum occurs when L = -b/(2A) = -60/(2*(-1)) = 30 ---- Maximum Area occurs when Length = 30 and Width = 30 =--- Maximum Area is 30^2 = 900 sq units ====================================== Cheers, Stan H.