SOLUTION: How do I find the maximum area for a rectangle with a fixed perimeter of 120

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Question 602737: How do I find the maximum area for a rectangle with a fixed perimeter of 120
Found 2 solutions by rfer, stanbon:
Answer by rfer(12666) (Show Source):
You can put this solution on YOUR website!
a square is max'
120/4=30
30*30=900 sq units

Answer by stanbon(57384) (Show Source):
You can put this solution on YOUR website!
): How do I find the maximum area for a rectangle with a fixed perimeter of 120
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Area = L*W
Perimeter = 2L + 2W
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2L+2W = 120
L + W = 60
W = 60-L
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Substitute into the Area formula:
A = L(60-L)
A = 60L - L^2
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Rearrange: A = -L^2+60L
Maximum occurs when L = -b/(2A) = -60/(2*(-1)) = 30
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Maximum Area occurs when Length = 30 and Width = 30
=---
Maximum Area is 30^2 = 900 sq units
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Cheers,
Stan H.