SOLUTION: leg a: x+1
leg b: x+3
and the hypotnus is: 2 the square root of 5
i am at 3xsquared+6x+0=0, but i'm confused if you could solve to get the missing numbers?
Algebra.Com
Question 601101: leg a: x+1
leg b: x+3
and the hypotnus is: 2 the square root of 5
i am at 3xsquared+6x+0=0, but i'm confused if you could solve to get the missing numbers?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
I can't figure where you got 
unless you were just guessing. BTW, that is almost always a poor strategy. In any case, toss it out and start over.
Use Pythagoras.
Substitute what you were given:
^2\ +\ (x\ +\ 3)^2\ =\ \left(2\sqrt{5}\right)^2)
Expand the binomials and square the constant.
Collect terms in the LHS
Divide by 2
Solve the factorable quadratic. Discard the negative root because it leads to the absurdity of negative measures of length. Calculate 
and 
John
My calculator said it, I believe it, that settles it
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