SOLUTION: log(-x)=-log(x)

Question 599021: log(-x)=-log(x)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log(-x)=-log(x)
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log(-x)+log(x) = 0
--
log[(-x)(x)] = 0
--
-x^2 = 10^0
---
-x^2 = 1
(1-x^2) = 0
(1-x)(1+x) = 0
x = 1 or x = -1
---
Checking:
log(-x)= -log(x)
Can x = 1 ?
log(-1) = -log(1)
No
------
Can x = -1 ?
log(1) = -log(-1)
No
-------------
Conclusion: No solution.
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Cheers,
Stan H.
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