SOLUTION: how do you factor by grouping c^2+3c+7cq+21q
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Question 596870: how do you factor by grouping c^2+3c+7cq+21q
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
c^2 + 3c + 7cq + 21q
Group the first two terms and the last two terms together. Factor a "c" from the first two terms, and a "7q" from the last two terms.
c(c+3) + 7q(c+3)
Now, factor out the common factor of (c+3):
(c+3)(c + 7q)
For additional explanation on FACTORING, please see my own website. The easiest way to find it is to use the easy to spell and easy to remember link www.mathinlivingcolor.com. On this single page website, there is a link at the bottom of the page that takes you to my Homepage.
Near the top of my homepage, look for the link "Basic, Intermediate, and College Algebra: One Step at a Time", and choose Basic Algebra (Chapter 2). Look for Section 2.07 Factoring by Grouping.
There you will find explanations that may be easier to understand than your traditional textbooks, and many of the exercises from these sections are solved in color on the "MATH IN LIVING COLOR" pages that go with these sections. There are also VIDEOS of me teaching this topic a few years before I retired. These videos are FREE, and you can see them by looking on my Homepage for the link "Rapalje Videos in Living Color." There are videos on Factoring in Basic Algebra and Intemediate Algebra.
If you like my website, please tell your friends and family. It's all FREE. You can contact me by Email at rapaljer@seminolestate.edu.
Dr. Robert J. Rapalje, Retired
Professor of Mathematics
Seminole State College of Florida
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