SOLUTION: Hi!! I need help with a problem: The lenght of a rectangle is 7 feet more than its width and the area is 120 square feet. Find the dimensions of the rectangle. I have no clue how

Question 596724: Hi!! I need help with a problem:
The lenght of a rectangle is 7 feet more than its width and the area is 120 square feet. Find the dimensions of the rectangle. I have no clue how to solve it.
Thank you,
I appreciate your help!
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
The way you are expected to solve the problem depends on what you have been studying in your class.

USING ALGEBRA (quadratic equations):
Let the width of the rectangle (in feet) be .
The length (in feet) is .
The area is --> -->
Solving (by factoring or using the quadratic formula), we get
and
Since the width must be a positive number, the width is feet,
and the length (in feet) is

USING FACTORS OF 120 (if studying divisibility and prime factors):
so it must have factors, including 1 and 120.
Those factors come in pairs that multiplied equal 120.
We just need to find the pair of factors that differ by 7.

So far I have listed 7 pairs of factors (14 factors).
There is one more pair, but
, so I do not need to go on.
The rectangle is 8 feet wide by 15 feet long.
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