SOLUTION: How do I solve for n? C(n, 5) = C(n, 7)

Algebra.Com
Question 573959: How do I solve for n? C(n, 5) = C(n, 7)
Found 2 solutions by solver91311, richard1234:
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


If you consider all of the possibilities for various combinations of things taken at a time and listed them in desceding order of , you would get a list that looks like:



















(Since , these two list items must be equidistant from the middle item in the list.)


















But since the s must all be integers, there can only be one item in the list between 7 and 5, namely



hence



So




John

My calculator said it, I believe it, that settles it
The Out Campaign: Scarlet Letter of Atheism


Answer by richard1234(7193)   (Show Source): You can put this solution on YOUR website!
Use the identity that C(n, k) = C(n, n-k). Here, we can let k = 5, n - k = 7. From here we get n - 5 = 7, n = 12.
RELATED QUESTIONS

Solve for n: C = 4r(n + p) (answered by checkley77)
C = 4r(n + p) solve for... (answered by Fombitz,nyc_function)
P=r-c/n, solve for... (answered by harpazo)
n ___=c-n, solve for n a+b (answered by edjones)
how do i solve for N? (answered by )
D=c-s/n solve for c (answered by Edwin McCravy)
an n=2,a,=4 and an=3a n-1 +1 How do I solve this? The possible answers are: a)13 b)0... (answered by ewatrrr)
I am working on cardinality of sets and the problem is: n(AᑎB)=6 n(BᑎC)=7 (answered by Edwin McCravy)
Solve for n. 18.5 * (10-n)/n=18.5 I know n is 5 but I'm not sure... (answered by joyofmath)