SOLUTION: Solve system of equations
2x+y+z=4
3x-y+4z=11
x-y+5z=20
Algebra.Com
Question 558692: Solve system of equations
2x+y+z=4
3x-y+4z=11
x-y+5z=20
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
2x+y+ z=4--------------1
3x-y+4z =11--------------2
x-y+5z= 20--------------3
Add the two
5x+y+5z =15 ------------- 4
consider equation 2 & 3 Eliminate y
Multiply 2 by -1
Multiply 3 by 1
we get
-3x+y-4 z=-11
x-y+5z = -4
Add the two
-2x+z = -15 -------------5 5
Consider (4) & (5) Eliminate x
Multiply 4 by 2
Multiply (5) by 5
we get 2
10 x + 10 z = 30
-10 x + 5 z = -75
Add the two
0 x + 15 z = -45
/ 15
z = -3
Plug the value of z in 5
-2 x + -3 = -15
-2 x = -12
x = 6
plug value of x & z in 1
12 + 1 y + -3 = 4
1 y = -12 + 3 + 4
y= -5
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