SOLUTION: The perimeter lf a rectangle is 86cm. If the lenght of the rectangle is 4x+7 and the width of the rectangle is 2x find the value of x
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Question 558042: The perimeter lf a rectangle is 86cm. If the lenght of the rectangle is 4x+7 and the width of the rectangle is 2x find the value of x
Answer by saifoo.khan(162) (Show Source): You can put this solution on YOUR website!
Perimeter = 2(L+B)
86 = 2[(4x+7)+2x]
Solve for x.
x = 6
So
widtht = 2x = 12
length = 4x+7 = 31
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Cheers/
Saifoo.khan
einstein.saifoo@gmail.com
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