SOLUTION: Richard found three consecutive even integers such that 7 times the sum of the first and third was 48 less than 10 times the second. What were the integers?

Question 557671: Richard found three consecutive even integers such that 7 times the sum of the first and third was 48 less than 10 times the second. What were the integers?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Call the consecutive even integers
, , and
given:

The consecutive even integers are -10, -12, and -14

OK
RELATED QUESTIONS
Find three consecutive even integers such that six times the sum of the first and the... (answered by MathLover1)

Find three consecutive even integers such that 3 times the sum of the first two is 48... (answered by Nate)

Please help me solve this word problem: Find three consecutive even integers such that (answered by ewatrrr)

Find three consecutive even integers, such that 7 times the middle integer is 10 more... (answered by mananth)

Find three consecutive even integers such that the sum of three times the first, and... (answered by sachi)

Horace Cope thought of three consecutive even integers and found that three times the sum (answered by Fombitz)

find three consecutive even integers such that four times the sum of the first and third... (answered by edjones)

Find. Three consecutive positive even integers such that the sum of the second and third... (answered by richwmiller)