SOLUTION: my problem: Where would you expect the vertex on the graph Y= (x-4)^2 +5 to be? Explain why? Thank You

Question 556844: my problem: Where would you expect the vertex on the graph Y= (x-4)^2 +5 to be? Explain why?
Thank You
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
my problem: Where would you expect the vertex on the graph Y= (x-4)^2 +5 to be? Explain why?
The graph is a parabola opening upward.
It has a minimum point at its vertex.
--
The smallest value y can have occurs
when x = 4.
That y-value is 5
---
So the vertex is at (4,5)
===============================
Cheers,
Stan H.
============
RELATED QUESTIONS
"where would you expect the vertex on the graph of y = (x - 4)^2 + 5 to... (answered by usyim88hk)

My problem...y=x^2+5 . I am supposed to graph this equation... so I make a function... (answered by Alan3354)

Im doing a homework worksheet on Solving Inequalities. We have to plot it on the graph.... (answered by stanbon)

Understanding why the graph looks the way it does: f(x) = (4(x-5))/((x+2)(10-x)) I... (answered by stanbon)

Ernie Thayer1 hits a baseball and it travels for 409.6 feet before it lands. When he hits (answered by richard1234)

Question: Consider the graphs of y=x^2 and y=x^2-6... a. Will either graph be... (answered by ewatrrr)

Please help me!!!! My problem says to graph each quadratic equation and state the vertex (answered by stanbon)

Hi! I am going nuts with this problem. They gave me a graph with a "launch area" and... (answered by richwmiller)

I would like help to find 5 points on the graph that can also be solutions to this... (answered by rwm)