SOLUTION: Using the elimination process how do you find
-8x+4y=-7
4x-2y=-1
3x+7y=10
5x=7-2y
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Question 548422: Using the elimination process how do you find
-8x+4y=-7
4x-2y=-1
3x+7y=10
5x=7-2y
Answer by Maths68(1474) (Show Source): You can put this solution on YOUR website!
..........(1)
...........(2)
Multiply by -2 both sides of equation (2)
...........(3)
LHS of equation (1) and (3) are same but RHS of both equation is different. It means that values of x and y for both equation are different. Therefore it is impossible to know the value of x and y by solving these two equations.
.............(1)
..............(2)
Multiply (1) by 5 and (2) by 3
.............(3)
..............(4)
Subtract (4) from (3)
.............(3)
..............(4)
----------------
Put the value of y in (1)
.............(1)
(x,y)=(1, 1)
Check
------
Put the values of x and y in (1)
.............(1)
Put the values of x and y in (2)
..............(2)
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