SOLUTION: 24y^2+2y-2=0

Question 544740: 24y^2+2y-2=0
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
24y^2+2y-2 = 0
Divide every term by 2.
2(12y^2 + y - 1) = 0

12y^2 + y - 1 = 0

12y^2 + 4y - 3y - 1 = 0

12y^2 + 4y becomes 4y(3y + 1)

-3y - 1 becomes -(3y + 1)

(4y - 1)(3y + 1) = 0

Set each factor to zero and solve for y.

4y - 1 = 0

4y = 1

y = 1/4

3y + 1 = 0

3y = -1

y = -1/3

The answer for y should be y = 1/4 and y = -1/3.

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