SOLUTION: its dividing polynomials if its possible work would be nice
(6t^3+5t^2+9)/(2t+3)
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Question 543941: its dividing polynomials if its possible work would be nice
(6t^3+5t^2+9)/(2t+3)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(6t^3+5t^2+9)/(2t+3)
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(2t+3))6t^3+5t^2+9
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1st piece of the quotient: 3t^2
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Multiply: 3t^2(2t+3) = 6t^3+9t^2
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Subtract from 6t^3+5t^2+9 to get: -4t^2+9
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2nd piece of the quotient: -2t
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Multiply: -2t(2t+3) = -4t^2-6t
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Subtract from 4t^2+9 to get: -6t-9
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3rd piece of the quotient: -3
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Multiply -3(2t+3) = -6t-9
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Subtract from -6t-9 to get: 0
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Final Answer: 3t^2-2t-3
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Cheers,
Stan H.
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