SOLUTION: A sequence begins 2,14,26,38,50 and each term is 12 more than the last. Whats the equation?

Algebra.Com
Question 543552: A sequence begins 2,14,26,38,50 and each term is 12 more than the last. Whats the equation?
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
A sequence begins 2,14,26,38,50 and each term is 12 more than the last. Whats the equation?
-----------
term(n+1) = term(n) + 12
-----
term(n) = 2 + 12n, n = 0,1,2,3...

RELATED QUESTIONS

List the first 10 terms of each of these sequences , a)the sequence that begins with 2... (answered by KMST)
Write the first four terms of a sequence in which the first term is 2 and each term is 6... (answered by checkley77)
A sequence starts with 5, and each term, other than the first, is 3 times the previous... (answered by stanbon)
The first term in a sequence of number is 2. Each even-numbered term is 3 more than the... (answered by sudhanshu_kmr)
in the jama's sequence each number after the second term is sum of the two terms before... (answered by ikleyn)
``write the first six terms of the sequence 2. an=(n+1)^3 4. an=n/n+3 write the... (answered by CubeyThePenguin)
3, 5,–5... The first term in the sequence of numbers shown above is 3. Each... (answered by Edwin McCravy)
12^10, (12^10 + 12^10), (12^10 + 12^10 + 12^10), ... In the sequence above, the first... (answered by KMST)
Which is larger,the 10th term of an arithmetic sequence that begins with the term 0and... (answered by ikleyn)