# SOLUTION: Write equation in slope-intercept form for the line that passes through (5, 0) and is perpendicular to the line described by y=-5/2x +6

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 Question 542888: Write equation in slope-intercept form for the line that passes through (5, 0) and is perpendicular to the line described by y=-5/2x +6 Answer by lmeeks54(105)   (Show Source): You can put this solution on YOUR website!The slope-intercept form of an equation is: y = mx + b, where: m = the slope of the line b = the y intercept (where x = 0) ... Given: y = -5/2 x + 6 line passes through the point (5, 0). Note points are in the form (x, y) ... problem: find a line parallel to line given above. Parallel means has to have the same slope. ... When we have a point, like (5, 0), that means that point is a solution to the equation. We already know m (slope), x, and y, we need to solve for b to create our parallel line: ... Given: m = -5/2 (or -2.5) x = 5 y = 0 Find b ... 0 = -5/2 (5) + b 0 = -12.5 + b ... add 12.5 to both sides: 12.5 = b ... Solution equation is: y = -2.5 x + 12.5 ... cheers, Lee