SOLUTION: A.40% antifreeze solution is to be mixed with a 70% solution to get 90 L of a 50% solution. How many liters of the 40% & the 70% will be needed?
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Question 535266: A.40% antifreeze solution is to be mixed with a 70% solution to get 90 L of a 50% solution. How many liters of the 40% & the 70% will be needed?
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
(x)(40%) + (90 - x)(70%) = (90)(50%)
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