SOLUTION: Find an equation for the line with the given properties. Express the equation in slope-intercept form. Containing the points P=(-2,1) and Q=(-1,-1)

Question 524148: Find an equation for the line with the given properties. Express the equation in slope-intercept form.
Containing the points P=(-2,1) and Q=(-1,-1)
Found 3 solutions by stanbon, oberobic, solver91311:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Express the equation in slope-intercept form.
Containing the points P=(-2,1) and Q=(-1,-1)
---------------------
slope = (-1-1)/(-1--2) = -2/1 = -2
------------------------
Form y = mx +b
---
You know m = -2 and y = 1 when x = -2.
Solve for "b";
1 = -2*-2 + b
b = -3
-----
Equation:
y = -2x-3
=====================
Cheers,
Stan H.
=====================
Answer by oberobic(2304)   (Show Source): You can put this solution on YOUR website!
m = (1-(-1)) / (-2-(-1))
.
m = 2 / -1
.
m = -2 = slope
.
y = -2x + b
.
Use one of the points to find 'b'
.
1 = -2*(-2) + b
.
1 = 4 + b
b = -3
.
y-intercept occurs when x=0, which is the point (0,-3).
.
The equation in slope-intercept form is:
.
y = -2x -3
.
x-intercept occurs when y=0, so set y=0 and find x
.
0 = -2x -3
.
2x = -3
.
x = -3/2
.
So, the x-intercept = (-3/2, 0).
.
A graph is always helpful.
.

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!

Use the two-point form of an equation of a line:

where and are the coordinates of the given points.

Simplify and arrange your resulting equation into slope-intercept form, namely:

John

My calculator said it, I believe it, that settles it

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