SOLUTION: two integers differ by 1 the sum of their reciprocals equals to 7 divided by their product.find the two integers.
Algebra.Com
Question 519517: two integers differ by 1 the sum of their reciprocals equals to 7 divided by their product.find the two integers.
Answer by mananth(16949) (Show Source): You can put this solution on YOUR website!
x-y = 1................1
1/x +1/y = 7/xy
(x+y)/xy = 7/xy
x+y =7................2
add (1) & (2)
2x=8
x=4
y=3
RELATED QUESTIONS
two integers differ by two and the sum of their sqaures is 74. find the... (answered by Alan3354)
two integers differ by four while their squares differ by 200. What is the product of the (answered by Fombitz)
Find two consecutive integers such that the sum of their reciprocals is... (answered by ankor@dixie-net.com)
please help me solve this equation
Two positive integers differ by 6. their product is... (answered by ikleyn)
Two positive numbers differ by 4. If the sum of their reciprocals is 2/3, find these two... (answered by ben720)
Two numbers differ by 6 and their reciprocals differ by 8/15.Find the... (answered by solver91311)
4. Two numbers differ by 9 and the sum of their reciprocals is 5/12. Find the numbers. (answered by math_tutor2020)
1. the product of two consecutive integers is 600.find the integers.(show working out)... (answered by richwmiller,oberobic)
The product of two consecutive positive integers is 1 more than their sum. Find the... (answered by ankor@dixie-net.com)