SOLUTION: Suppose a radioactive isotope is such that five-sixths of the atoms in a sample decay after nine days. Find the half-life of this isotope.
Round your answer to 2 decimal places.
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Question 515381: Suppose a radioactive isotope is such that five-sixths of the atoms in a sample decay after nine days. Find the half-life of this isotope.
Round your answer to 2 decimal places.
______ days.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Suppose a radioactive isotope is such that five-sixths of the atoms in a sample decay after nine days.
Find the half-life of this isotope.
:
the radioactive decay formula: A = Ao*2^(-t/h), where
A = Amt remaining after t time
Ao = Initial Amt
t = time
h = half-life of substance
:
Let initial amt = 1
1*2^(-9/h) =
Use natural logs
ln(2^(-9/h)) = ln(5/6)
The log equiv of exponents
*ln(2) = ln(5/6)
=
using a calc
= -.263
-.263h = -9
h =
h = 34.2 days, half-life of substance
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