SOLUTION: solve t^2 + 4t = 1

Question 477044: solve
t^2 + 4t = 1
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve
t^2 + 4t = 1
t^2 + 4t -1 = 0
Use the Quadratic Formula:
t = [-b +- sqrt(b^2-4ac)]/(2a)
---
t = [-4 +- sqrt(16-4*1*-1)]/2
---
t = [-4 +- sqrt(20)]/2
---
t = [4 +- 2sqrt(5)]/2
---
t = 2+sqrt(5) or t = 2-sqrt(5)
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Cheers,
Stan H.
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