SOLUTION: How do I solve a problem like this: find vertex of parabola y=3x^2+6x-12 Thanks, J

Question 468414: How do I solve a problem like this:
find vertex of parabola
y=3x^2+6x-12
Thanks,
J
Found 2 solutions by MathLover1, josmiceli:
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
......standard form
When a function is in standard form rather than vertex form , we cannot simply look at the function and find the vertex of (h, k). There are two ways to approach this problem.
Using a formula: The x-value of the vertex can be found using the formula y-value.
......, and

the vertex is (h, k)=(-1, -15)

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!

The vertex is at either the minimum or maximum of the
parabola. The coefficient of the squared term is positive,
so it will have a minimum.
When the equation is in the form .
The x-coordinate of the minimum is at

x =
x =
Now to find the y-coordinate,

The vertex is at (-1,-15)
Here is a plot:

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