SOLUTION: how to solve by substitution?
problems:
1) x + y = -6 and 3x - 3y = -18
2) - 4x + 2y = 10 and 8x - 8y = -16
3) -6x + 4y = 2 and 6x - 2y = -10
Algebra.Com
Question 465399: how to solve by substitution?
problems:
1) x + y = -6 and 3x - 3y = -18
2) - 4x + 2y = 10 and 8x - 8y = -16
3) -6x + 4y = 2 and 6x - 2y = -10
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
1)
........1
.........2......both sides multiply by
------------------------------------
.........2
.....2....add to 1
--------------------------------------
........1
..........2
--------------------------------------
........1.plug in
check:
........1
2)
........1
........2.....both sides multiply by
--------------------------
................add to 1
-------------------------------
........1
...........2
---------------------------
........2.
3)
........1 .....solve for
..........2
-----------------------------
........1
.........substitute in 2
----------------------------------------------
..........2....solve for
now find
4)
.....1 .....solve for
...2
-------------------------
.....1
.................substitute in 2
-------------------------------
...2..solve for
now find
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