SOLUTION: Practice Test Question.
How many liters of a 60%-alcohol solution must be mixed with 70 liters of a solution that is 90% alcohol to get the solution that is 70% alcohol?
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Question 448552: Practice Test Question.
How many liters of a 60%-alcohol solution must be mixed with 70 liters of a solution that is 90% alcohol to get the solution that is 70% alcohol?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
.60x+70*.9=(70+x).7
.60x+63=49+.7x
14=.1x
x=140
You need 140 liters of 60% alcohol for your mix..
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