SOLUTION: what is the vertex, focus, and directrix of y=1/3x^2-2x+6

Question 443938: what is the vertex, focus, and directrix of y=1/3x^2-2x+6
Answer by poliphob3.14(115) (Show Source): You can put this solution on YOUR website!
First we need to find the standard form of the parabola equation:
=> => .
The final equation is the equation of parabola with vertex (3, 3).
Since 4c=3 we get c=3/4, and the focus is (3, 3+3/4) or (3, 15/4).
The directrix is y=3-3/4=9/4.

RELATED QUESTIONS
What is the vertex, focus, and directrix for this equation:... (answered by lwsshak3)

What is the focus, vertex and directrix of the parabola... (answered by lwsshak3)

What are the focus and the directrix of the graph of x = 1/24y^2? focus (0, �6),... (answered by lwsshak3)

What are the focus and the directrix of the graph of x = 1/24y^2? focus (0, �6),... (answered by jsmallt9)

what is the vertex, focus, and equation of directrix (y+3)^2 = -4(x-2) (answered by MathLover1)

What is the vertex, axis of symmetry, focus, and directrix of the parabola... (answered by MathLover1)

How do I find the vertex and focus and directrix of... (answered by josgarithmetic)

Can you please help. (33) Find the vertex, focus, and directrix of the graph of the... (answered by Nate)

What is the vertex, focus, and directrix of... (answered by lwsshak3)