SOLUTION: what is the number of complex roots, real roots and imaginary roots for this equation, x^3-6x^2+x+34=0
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Question 443930: what is the number of complex roots, real roots and imaginary roots for this equation, x^3-6x^2+x+34=0
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Use the rational roots theorem. If a polynomial equation with rational coefficients has a rational root, then that root will be of the form
where
is an even divisor of the constant term of the equation and
is an even divisior of the lead coefficient. Possible rational roots are
,
,
, and
.
Use synthetic division to find the first real and rational root. This is an equation of odd degree with rational coefficients, hence there must be at least one real root and it must be rational. Review the process of synthetic division at Purple Math: Synthetic Division Be certain to review all four pages.
The quotient from your successful synthetic division will provide the coeffients of a quadratic equation. From these coefficients, you can calculate the discriminant to determine the character of the remaining two roots.
John

My calculator said it, I believe it, that settles it
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