SOLUTION: here is the problem im unsure of how to do..
Solve the equation and check for extraneous solutions:
3(x-5)^3/2-6=18
i really dont know how to do this. If you could help m
Algebra.Com
Question 440168: here is the problem im unsure of how to do..
Solve the equation and check for extraneous solutions:
3(x-5)^3/2-6=18
i really dont know how to do this. If you could help me that would be great. Thank you
Answer by rwm(914) (Show Source): You can put this solution on YOUR website!
3(x-5)^3/2-6=18
add 6 to both sides
3(x-5)^3/2=24
divide both sides by 3
(x-5)^3/2=8
square both sides
(x-5)^3=64
get the cube roots
x-5=
x-5=4
x=9
(x-5)^3-64 = 0
x^3-15 x^2+75 x-189 = 0
x = 3-2 i sqrt(3)
x = 3+2 i sqrt(3)
x=9
RELATED QUESTIONS
How do I solve this equation and check for extraneous solutions?
3 sqrt w + 1 =... (answered by unlockmath,stanbon)
Solve the equation. Check for extraneous solutions.
|4x|=28
I dont understand how to do (answered by algebrahouse.com)
Solve the equation. Check for extraneous solutions.... (answered by Alan3354)
Solve the equation (x/2)=(2x-3), and check for extraneous... (answered by MathLover1)
Solve the equation √(x-3) + √(x+2) = 5. Be sure to check for extraneous (answered by greenestamps)
how do I solve this problem for radical equations.
1. (x-2)to the 1/3 power=5 Check... (answered by stanbon)
=/ Alright so i just got off of long term suspention cause someone decided to fight me... (answered by stanbon)
OK, I am so not worthy of your math wisdom :) (thank you for helping).
There are still a (answered by longjonsilver)
Solve the absolute value equation and check for extraneous solutions... (answered by edjones)