SOLUTION: solve by factoring: 1-16x^2=0
Algebra.Com
Question 438372: solve by factoring: 1-16x^2=0
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
we can rewrite:
1-16x^2=0
as
1^2- (4x)^2=0
this is now a "difference of squares" which factors to:
(1-4x)(1+4x) = 0
x = {-1/4, 1/4}
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