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put this solution on YOUR website!Find the slope-intercept form for the equation of the line which passes through the point (–1, 3) and has a slope of –2.
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Form: y = mx+b
You have y = 3 when x = -1 and you have m = -2
Solve for "b";
3 = -2*3+b
3 = -6+b
b = 9
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Equation:
y = -2x+9
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Find the slope-intercept form for the equation of the line
which passes through the point (–3, 2) and the origin
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You have y = 0 when x = 0
You have slope = (2-0)/(-3-0) = -2/3
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Solve for "b":
y = mx + b
0 = (-2/3)*0 + b
b = 0
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Y = (-2/3)x
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Cheers,
Stan H.
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