Hi

sample size is 24 with sample mean 113 and standard deviation 10

ME = 1.645[10/sqrt(24)] 

90% confidence interval 				

CI: 113-ME < u < 113 +ME

		

80% confidence interval		

ME = 1.282[10/sqrt(24)] 

CI: 113-ME < u < 113+ME



Folowing a summary of various confidence interval values

	a	a/2	crtical regions	

90%	0.1	5%	z <-1.645	z >+1.645

95%	0.05	2.50%	z <-1.96	z >+1.96

98%	0.02	1%	z <-2.33	z >+2.33

99%	0.01	0.50%	z<-2.575	z >+2.575

 

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