SOLUTION: Andy is four times as old as Wendy . In twelve years Wendy's age will be half of Andy's.find their ages now.
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Question 424021: Andy is four times as old as Wendy . In twelve years Wendy's age will be half of Andy's.find their ages now.
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
"Andy is four times as old as Wendy . In twelve years Wendy's age will be half of Andy's.find their ages now."
x = Wendy's age now
4x = Andy's age now
x + 12 = Wendy's age in 12 years
4x + 12 = Andy's age in 12 years
x + 12 = (1/2)(4x + 12) {in twelve years, Wendy's age will equal half Andy's age}
x + 12 = 2x + 6 {used distributive property}
12 = x + 6 {subtracted x from both sides}
x = 6 {subtracted 6 from both sides}
4x = 24 {substituted 6, in for x, into 4x}
Wendy is 6 now and Andy is 24 now
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