Hi

finding all zeros of the function. 

f(x)=x^3-3x^2-6x+8  

      x^3-3x^2-6x+8   = 0  |If x = 1 then zero (1-3-6+8 = 0 )

   (x -1)(x-4)(x+2) =0  |Dividing x^3-3x^2-6x+8   by (x-1)

   ( x-1)=0  x = 1

    (x-4)=0  x = 4

    (x+2)=0  x = -2

      

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