SOLUTION: What are the steps to solving:
2^(x-1) = 16^(x+2) ?
Algebra.Com
Question 414926: What are the steps to solving:
2^(x-1) = 16^(x+2) ?
Answer by sudhanshu_kmr(1152) (Show Source): You can put this solution on YOUR website!
2^(x-1) = 16^(x+2)
=> 2^(x-1) = (2^4)^(x+2)
=> 2^(x-1) = 2^(4x+8)
here base are same so, compare exponent
x -1 = 4x+8
=> -3x = 9
=> x = -3
RELATED QUESTIONS
what are the steps to solving the equation... (answered by solver91311)
What are the steps to solving this problem?... (answered by ptaylor)
What are the steps to solving this absolute value question... (answered by htmentor)
what are the steps to solving a problem like this: (x+5)/(x+1)+(5)/(x-2)
(answered by stanbon)
What are the steps to solving the system
x^2+y^2=169
x-y=7
(answered by jojo14344)
What are the steps to solving this equation?
x^-3 + y ^-6
--------------
x^-6... (answered by checkley77)
2/(x-1) = 3/(x+3) + 1/(x+3)(x-1)
What are the first few steps to solving this equation (answered by stanbon)
What are the steps to solving a system using substitution. example:
y=x+2 y=2x-1. (answered by checkley71)
What are the steps to determine the restricted values?... (answered by Mathtut)