Hi

Using the vertex form of a parabola,  where(h,k) is the vertex

Sketching the first-quadrant portions of y=x^2+8x+16

 y = x^2+8x+16

 y= (x+4)^2 - 16 + 16

 y = (x+4)^2  |When x = 0, then y = 16

Cannot demonstrate here, however it would be the portion of the parabola

in the first-quadrant





 

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